x^2+3x=2.7

Solution for x^2+3x=2.7 equation:

x^2+3x=2.7

We move all terms to the left:

x^2+3x-(2.7)=0

We add all the numbers together, and all the variables

x^2+3x-2.7=0

a = 1; b = 3; c = -2.7;
Δ = b2-4ac
Δ = 32-4·1·(-2.7)
Δ = 19.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{19.8}}{2*1}=\frac{-3-\sqrt{19.8}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{19.8}}{2*1}=\frac{-3+\sqrt{19.8}}{2}
$